ifv=(3i+4j+5k)m/s is the instantaneous velocity of a body mass 1.50kg calculate its K.E

Question

ifv=(3i+4j+5k)m/s is the instantaneous velocity of a body mass 1.50kg calculate its K.E

Answer 1

I wish I knew your academic level. I will go with the basic.

velocityScalar=sqrt(3^2+4^2+5^2)
then KE= 1/2 mass*velocityScalar^2

Answer 2

I only want answer for this question I dintknow

Answer 3

To calculate the kinetic energy (K.E) of a body, you need to know its mass and velocity. In this case, you have been given the velocity vector ifv=(3i+4j+5k)m/s, and the mass of the body is 1.50 kg.

The formula for calculating kinetic energy is:

K.E = (1/2) * mass * velocity^2

First, calculate the magnitude of the velocity vector:

|velocity| = sqrt((3^2) + (4^2) + (5^2))

|velocity| = sqrt(9 + 16 + 25)

|velocity| = sqrt(50)

|velocity| = 7.07 m/s (approx)

Now, substitute the values into the formula:

K.E = (1/2) * 1.50 kg * (7.07 m/s)^2

K.E = (1/2) * 1.50 kg * 49.99 m^2/s^2

K.E ≈ 37.49 Joules (J)

So, the kinetic energy of the body is approximately 37.49 Joules.