Two pails contained a total of 21.8 liters of water. After 0.36 liters of water is poured from the small pail into big pail, the amount of water in the big pail is 9 times that in the small pail. How much water was in each pail at first?
Let x = big pail and y = small pail
Equation 1 : x + y = 21.8
Equation 2 : 9*(y - 0.36) + (y - 0.36) = 21.8
Therefore, big pail = 19.26 litres
Therefore, small pail = 2.54 litres
Well, it seems like those pails were quite the watering hole. Let's do a little math to figure it out.
Let's say the amount of water in the small pail was x liters. That means the amount of water in the big pail would be 21.8 - x liters.
After pouring 0.36 liters from the small pail into the big pail, the new amount of water in the big pail is 9 times that in the small pail. So, we can set up the equation 21.8 - x + 0.36 = 9x.
Now, let's solve for x. When we do the math, we find that x ≈ 2.41 liters.
Therefore, the small pail originally had approximately 2.41 liters of water, while the big pail had 21.8 - 2.41 ≈ 19.39 liters.
Let's assume that the amount of water in the small pail at first is x liters.
Therefore, the amount of water in the big pail at first would be (21.8 - x) liters (since the total is 21.8 liters).
After pouring 0.36 liters of water from the small pail into the big pail, the amount of water in the big pail becomes (21.8 - x + 0.36) liters.
According to the given condition, the amount of water in the big pail is 9 times that in the small pail:
(21.8 - x + 0.36) = 9x
Simplifying the equation:
21.8 - x + 0.36 = 9x
21.8 + 0.36 = 10x
22.16 = 10x
Dividing both sides of the equation by 10:
22.16/10 = x
x = 2.216
So, the amount of water in the small pail at first was approximately 2.216 liters.
Since the total amount of water is 21.8 liters, the amount of water in the big pail at first would be:
21.8 - 2.216 = 19.584 liters
Therefore, at first, the small pail contained approximately 2.216 liters of water and the big pail contained approximately 19.584 liters of water.
To solve this problem, let's use algebraic equations.
Let's assume that the amount of water in the small pail is "x" liters and the amount of water in the big pail is "y" liters at the beginning.
According to the given information, we know that the total amount of water in both pails is 21.8 liters. So we can write the equation:
x + y = 21.8 ----(1)
We are also given that after pouring 0.36 liters of water from the small pail into the big pail, the amount of water in the big pail is 9 times that in the small pail. We can express this as:
y = 9x - 0.36 ----(2)
Now, we have a system of two equations (Equations 1 and 2) with two variables (x and y). We can solve this system to find the values of x and y.
Let's substitute the value of y from Equation 2 into Equation 1:
x + (9x - 0.36) = 21.8
Simplifying the equation, we get:
10x - 0.36 = 21.8
Add 0.36 to both sides of the equation:
10x = 21.8 + 0.36
Combine like terms:
10x = 22.16
Divide both sides by 10:
x = 2.216
Now, substitute the value of x back into Equation 1 to find the value of y:
2.216 + y = 21.8
Subtract 2.216 from both sides:
y = 21.8 - 2.216
Solve the equation:
y = 19.584
Therefore, the amount of water in the small pail at first (x) is 2.216 liters, and the amount of water in the big pail at first (y) is 19.584 liters.