An airplane has a mass of 3.19 × 104 kg and takes off under the influence of a constant net force of 1.56 × 104 N. What is the net force that acts on the plane's 82.1-kg pilot?
well, something important is missing. Is this "net force" the accelerating force, I assume so. But the plane, and pilot also are under the influence of gravity, which is downward, and the accelerating force is almost perpendicular to gravity.
So ignoring gravity, and pilots weight...
accelerlation=massapirplane/netforce
then force on pilot,neglecting weight, is acceleration*82.1
To find the net force acting on the plane's pilot, we can use Newton's second law of motion, which states that the net force (Fnet) acting on an object is equal to the product of its mass (m) and acceleration (a). Mathematically, it can be written as:
Fnet = m * a
In this case, we have the mass of the plane (m_plane) and the net force acting on it (Fnet_plane). We also know that the mass of the pilot (m_pilot) is 82.1 kg. We need to find the net force acting on the pilot (Fnet_pilot).
First, we can find the acceleration of the plane using the formula:
a_plane = Fnet_plane / m_plane
Substituting the given values:
a_plane = (1.56 × 104 N) / (3.19 × 104 kg)
Now, we can use this acceleration to find the net force acting on the pilot, applying Newton's second law:
Fnet_pilot = m_pilot * a_plane
Substituting the values:
Fnet_pilot = (82.1 kg) * a_plane
Calculating the acceleration (a_plane) and substituting it into the equation:
Fnet_pilot = (82.1 kg) * [(1.56 × 104 N) / (3.19 × 104 kg)]
Simplifying the equation:
Fnet_pilot = (82.1 kg) * (0.4896)
Fnet_pilot ≈ 40.150 kg･m/s²
Therefore, the net force acting on the plane's 82.1-kg pilot is approximately 40.150 kg･m/s².