physics

When you take a bath, how many kilograms of hot water (48°C) must you mix with cold water (13°C) so that the temperature of the bath is 36°C? The total mass of water (hot plus cold) is 185 kg. Ignore any heat flow between the water and its external surroundings.

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  1. Call mass hot water H.
    Then mass cold water is 185-H.
    H*specific heat water x (Tfinal-Tinitial) + (185-H)*specific heat water x (Tfinal-Tinitial) = 0
    Solve for H and C.
    Check my thinking. Post your work if you get stuck.

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  2. When you are taking a bath, how many kilograms of hot water at 48oC must you mix with cold water at 12oC so that the temperature of the bath is 36oC? Assume the total mass of water (hot water + cold water) is 90kg.

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