Math

Consider the following cubic curve:
f(x)=−x3 −x2 +16x+16

1. Calculate f′(x).
2. Calculate f′′(x).
3. Find the x values such that f(x) = 0.

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asked by R
  1. Assuming you meant:
    f(x)=?x^3 ?x^2 +16x+16

    f ' (x) = -3x^2 - 2x + 16
    f ''(x) = -6x - 2

    If you are studying Calculus or Pre-Calculus, you MUST know how to do this.

    if f(x) = 0
    ?x^3 ?x^2 +16x+16 = 0
    x^3 + x^2 - 16x - 16 = 0
    by grouping,
    x^2(x+1) - 16(x+1) = 0
    (x+1)(x^2 - 16) = 0
    (x+1)(x-4)(x+4) = 0
    x = -1, 4, -4

    verification:
    http://www.wolframalpha.com/input/?i=plot+f(x)%3D%E2%88%92x%5E3+%E2%88%92x%5E2+%2B16x%2B16

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    posted by Reiny
  2. Why did you repost this question ??
    Just noticed that Steve answered it for you several days ago

    http://www.jiskha.com/display.cgi?id=1483135842

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    posted by Reiny

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