A man at the back of a crowd watches a parade by holding a plane mirror just above his head and the parade passes 6m behind his head and the mirror is 0.25m in front of the man. How far does the image appear to be from the man...

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how sir? i dont understan

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draw a ray diagram....

To solve this problem, we can use the concept of reflection in a plane mirror. The distance of the image from the man can be determined using the mirror equation.

The mirror equation relates the object distance (dₒ), the image distance (dᵢ), and the focal length (f) of the mirror:

1/dₒ + 1/dᵢ = 1/f

In this case, the object distance is the distance between the man's head and the parade (6m), and the mirror is 0.25m in front of the man.

Let's calculate the image distance:

1/dₒ + 1/dᵢ = 1/f

1/6 + 1/dᵢ = 1/0.25

Simplifying the equation:

1/dᵢ = 1/0.25 - 1/6

1/dᵢ = (6 - 0.25) / (6 * 0.25)

1/dᵢ = (5.75) / 1.5

1/dᵢ ≈ 3.83

To find the image distance (dᵢ), we take the reciprocal of 3.83:

dᵢ ≈ 1 / 3.83 ≈ 0.26 meters

Therefore, the image appears to be approximately 0.26 meters from the man.

from his real eyes, the object will be 6.25m. From the man in the image, it will appear 6m behind his head.