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AlgebraPlease check my answers
Posted by Jessie on Monday, October 18, 2010 at 3:48pm. I think I figured it outplease check I'm really stuck on these problems Simplify 6xy(3xy)^2? I think this is 2/3xy choices were 2/xy 3xy 2xy 2/3xy Simplify 12xyz^2/8x^2z
asked by Jessie on October 18, 2010 
AlgebraPlease check my answers
Posted by Jessie on Monday, October 18, 2010 at 3:48pm. I think I figured it outplease check I'm really stuck on these problems Simplify 6xy(3xy)^2? I think this is 2/3xy choices were 2/xy 3xy 2xy 2/3xy Simplify 12xyz^2/8x^2z
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X+y+z=1......(1) x^2+y^2+z^2=35........(2) x^3+y^3+z^3=97.........(3) solution but from 3 (x^3+y^3)=(x+y)^33xy(x+y)......(4) puting 4 into 3 bck (x+y)^33xy(x+y)+z^3=97.......(5) now from 1 x+y=1z......(6) putin 6 into 7 we have
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I have to simplify (x^5y^4)^4(3x^2y)^2(1/3xy) I did (x^20y^16)(9x^4y^2)(1/3xy) (9x^24y^18)(1/3xy) 3x^25y^19 Is this correct? Thank you for your help!
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Find the derivative of sin(2x + 3y)= 3xy + 5y2. I have this so far 1) cos(2x+3y) * d/dx (2x+3y)= 3xy' + 3y + 5y' 2) cos (2x+3y) * [2 + 3y']= 3xy' + 3y + 5y' 3) 3y' cos (2x+3y) + 2cos(2x+3y)= 3xy' + 3y + 5y' 4) 3xy' + 5y' 
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multiply the following polynomial 3x(y^2+2y^2) answer choices 3xy^26xy^2' 3xy^2gxy^2 3xy^2+5y^2 9xy^2 The last one was the answer. Can you tell me how the answer was solved? Thanks!
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the directions are to determine whether or not the equation is exact if so then solve it. the question is (xy^3+ysinx)dx = (3xy^2+2ycosx)dy i solve and i got that it is exact because My is 3y^2+2ysinx and Nx is 3y^2+2ysinx
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I have no clue how to do this as no values were given and im confused. can someone explain plz? if x^3y^3=m and xy=N, express xy in terms of M and N This is one of those pure manipulation problems. you have to know that x^3y^3
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asked by Anonymous on September 14, 2014 
bobpursly,
Is this correct now after i revised it Multiply. 3xy^2(5xy4x+6y) 3xy^2(5xy)=15x^2y^3 3xy^2(4x)=12x^2y^2 3xy^2(6y)=18xy^3 so i get from this 15x^2y^312x^2y^2+18xy^3 correct awsome i just thought that the 15x^2y^312x^2y^2
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algebra 2
(w + 2t)(w^2  2wt + 4t^2) (x + y)(x^2 3xy + 2y^2) =x^3  3x^2y + 2xy^2 + x^2y 3xy^2 + 2y^3 = x^32x^2yxy^2+2y^3
asked by Reina Bonilla on January 21, 2015