Hello,
Is nano3 + h2o -> naoh + hno3 correct?
In chemistry, since there are more than 26 elements, some elements are represented by two letters of the alphabet. The first (or the only) letter of an element is ALWAYS written in capital letters to avoid confusion, since formulas of compounds are written without delimiters.
For example, CO stands for carbon monoxide, Co stands for cobalt.
Back to the equation you posted, if the reactants and products are interchanged, then it would be correct.
To paraphrase MathMate's answer, no, it isn't correct. I have used, quite often, the CO example, but I add another. CO is carbon monoxide, Co is cobalt, and co is the abbreviation for company.
Hello!
To determine if the chemical equation nano3 + h2o -> naoh + hno3 is correct, we need to check if it follows the law of conservation of mass. According to this law, the number of each type of atom must be the same on both sides of the equation.
Let's break down the equation and count the atoms:
On the left side of the equation:
- nano3: 1 Na, 1 N, and 3 O
- h2o: 2 H and 1 O
On the right side of the equation:
- naoh: 1 Na, 1 O, and 1 H
- hno3: 1 H, 1 N, and 3 O
Comparing the counts, we find that the number of atoms is not balanced. The left side of the equation has an extra nitrogen (N) atom compared to the right side, and the right side has an extra hydrogen (H) atom compared to the left side.
Therefore, the chemical equation nano3 + h2o -> naoh + hno3 is not balanced.
To balance the equation, we need to adjust the coefficients (numbers in front of the chemical formulas). The balanced equation should be:
2 nano3 + 2 h2o -> 2 naoh + hno3
This equation now follows the law of conservation of mass, as the number of each type of atom is the same on both sides.