How much heat is absorbed by a 70g iron skillet when its temperature rises from 24oC to 110oC? joules

heat=mass*SpecificHeatconstant*Tempchange.

look up the specific heat constant for iron.

sooo 70g * 24 oC = 110 Oc?

Nope. LOOK UP THE SPECIFIC HEAT constant OF IRON

change temp=110-24=???

To calculate the heat absorbed by the iron skillet, we need to use the heat capacity formula:

Q = m * c * ΔT

Where:
Q = Heat absorbed (in Joules)
m = Mass of the iron skillet (in grams)
c = Specific heat capacity of iron (in J/g·°C)
ΔT = Change in temperature (in °C)

First, let's convert the mass from grams to kilograms:
m = 70g = 70/1000 = 0.07 kg

Next, we need to find the specific heat capacity of iron. The specific heat capacity of iron is approximately 0.45 J/g·°C.

Now we can calculate the change in temperature:
ΔT = 110°C - 24°C = 86°C

Plugging the values into the formula, we get:
Q = 0.07 kg * 0.45 J/g·°C * 86°C

Calculating that, we find:
Q = 270.9 J

Therefore, the iron skillet absorbs approximately 270.9 Joules of heat.