Math

A number of two digits is such that twice the ten digits is 8 less than seven times the unit digit. When the digits are reversed, the number is decreased by 9. What is the number?

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  1. let the tens digit be x, and the unit digit be y
    So the number is 10x + y,
    the number reversed is 10y + x

    10x+y - (10y+x) = 9
    9x - 9y = 9
    x - y = 1 or x = y+1 **

    2x = 7y-8
    sub in **
    2(y+1) = 7y - 8
    2y + 2 = 7y - 8
    -5y = -10
    y = 2

    The number is 32

    check:
    the number reversed is 23, which is 9 less than 32.
    Twice the ten digit is 6
    7 times the unit digit = 14, which is 8 less than 6
    My answer is correct.

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    posted by Reiny
  2. Pls how did you get 32 as the number

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