Hello,
If I add water to a solid, how do i represent it in a equation with phases?
for example the NaNO3 was the solid in this case and H2O was the liquid,
does NaNO3 turns into an aqueous or stays as solid when I write the equation?
Which one would be correct?
1) NaNO3(s) + H2O(l) = HNO3(aq) + NaOH(aq)
or
2)NaNO3(aq) + H2O(l) = HNO3(aq) + NaOH(aq)
Thanks!
it is in aq phase when it reacts:
NaNO3(aq)+...
I don't understand how it turns into aq when its a solid I add into the water, isn't only the products turn into aq?
nope, once dissolved, it is in aqueous solution.
So despite having to shake the test tube for it to dissolve into the water, NaNO3 in this case would be considered as Aqueous?
To represent the addition of water to a solid in an equation with phases, you need to consider whether the solid dissolves completely in water or not.
In the case of NaNO3, it is a water-soluble compound, meaning it dissolves completely in water to form an aqueous solution. So, when you add water to NaNO3, it will dissolve and form an aqueous solution.
Therefore, the correct representation of the equation would be:
NaNO3(s) + H2O(l) → NaNO3(aq)
This equation indicates that NaNO3 initially exists as a solid (s) and then dissolves in water (l), resulting in an aqueous solution (aq) of NaNO3.
If you further react the NaNO3 solution with certain chemicals, you can then write the complete balanced equation:
NaNO3(aq) + H2O(l) → HNO3(aq) + NaOH(aq)
This equation shows the reaction between the NaNO3 solution and water, resulting in the formation of nitric acid (HNO3) and sodium hydroxide (NaOH), both being in aqueous form (aq).
So, in summary:
- NaNO3 starts as a solid (s) when added to water.
- After dissolving completely in water, it becomes an aqueous solution (aq).
- Any subsequent reactions involving NaNO3 in solution would be represented with NaNO3(aq).
Hope this helps clarify the representation in the equation!