A boy has rs728 in denomination of rs 2 notes, rs 5 notes and rs 10 notes in the ratio of 3:2:4, respectively. What is the total number of notes he has?
(A)104 (B)127
(C)100 (D)117
Add up the value of each kind of note:
2(3x)+5(2x)+10(4x) = 728
now find x, and the total number of notes is
3x+2x+4x = 9x
or, see how much 1 set of 9 notes is worth: 2*3+5*2+10*4 = 56
728/56 = 13
So there are 13 sets of 9 notes...
117
To find the total number of notes the boy has, we need to find the number of notes in each denomination.
Let's assume the number of rs 2 notes is 3x, the number of rs 5 notes is 2x, and the number of rs 10 notes is 4x, where x is a common factor.
Since the total value of all the notes is rs 728, we can set up the equation:
(2 * 3x) + (5 * 2x) + (10 * 4x) = 728
Simplifying the equation:
6x + 10x + 40x = 728
56x = 728
x = 728 / 56
x ≈ 13
Now we can find the number of notes in each denomination:
Number of rs 2 notes = 3x ≈ 3 * 13 = 39
Number of rs 5 notes = 2x ≈ 2 * 13 = 26
Number of rs 10 notes = 4x ≈ 4 * 13 = 52
The total number of notes he has is 39 + 26 + 52 = 117.
Therefore, the answer is (D) 117.