The specific heat of silver is 0.24 J/g*C. If 15.4 g of silver absorb 332 J heat, how much will the temperature of the silver increase?
q = mass Ag x specific heat Ag x delta T.
Substitute and solve for dT.
To calculate the temperature increase, you can use the formula:
q = mcΔT
Where:
q = heat absorbed or released (in joules)
m = mass of the substance (in grams)
c = specific heat capacity of the substance (in J/g°C)
ΔT = change in temperature (in °C)
Given:
m (mass of silver) = 15.4 g
c (specific heat of silver) = 0.24 J/g°C
q (heat absorbed) = 332 J
Rearranging the formula to solve for ΔT:
ΔT = q / (m * c)
Substituting the given values:
ΔT = 332 J / (15.4 g * 0.24 J/g°C)
Calculating:
ΔT = 332 J / (3.696 g°C)
ΔT ≈ 89.9 °C
Therefore, the temperature of the silver will increase by approximately 89.9 °C.
To find the increase in temperature of the silver, we can use the equation:
Q = mcΔT
where Q is the heat absorbed by the silver, m is the mass of the silver, c is the specific heat of silver, and ΔT is the change in temperature.
Given:
Q = 332 J
m = 15.4 g
c = 0.24 J/g°C
Let's rearrange the equation to solve for ΔT:
ΔT = Q / (mc)
Substituting the given values:
ΔT = 332 J / (15.4 g * 0.24 J/g°C)
Now, let's calculate the value of ΔT:
ΔT = 332 J / (3.696 g°C)
ΔT ≈ 89.9 °C
Therefore, the temperature of the silver will increase by approximately 89.9 °C.