it is found that the number of raisins in a box of a popular cereal is normally distrubuted, with a mean of 133 raisins per box and a standard deviation of 10 raisins. my cereal box has 152 raisins, what is the z-score for this box of cereal?
(152-133)/10
To find the z-score for the cereal box with 152 raisins, you can use the formula:
z = (x - μ) / σ
where:
x = the value of interest (152 raisins)
μ = mean (133 raisins)
σ = standard deviation (10 raisins)
Substituting the values into the formula:
z = (152 - 133) / 10
Calculating the z-score:
z = 19 / 10
z = 1.9
Therefore, the z-score for this box of cereal is 1.9.
To find the z-score for a box of cereal with 152 raisins, you can use the formula:
z-score = (x - mean) / standard deviation
where:
x = number of raisins in the box
mean = mean number of raisins per box
standard deviation = standard deviation of the number of raisins per box
In this case:
x = 152
mean = 133
standard deviation = 10
Plugging in the values, we get:
z-score = (152 - 133) / 10
= 19 / 10
= 1.9
Therefore, the z-score for this box of cereal is 1.9.