A+force+of+12+N+pulls+a+block+of+mass+3.5kg+through+a+rope+of+mass+0.5kg.+The+block+is+resting+on+a+horizontal+frictionless+surface.+what+is+the+force+of+reaction+exerted+by+the+block+on+the+rope
acceleration of system: 12/4.0=3m/s
force on block: 3.5kg*3m/s=11.5N
reaction force= 11.5N (Newtons third law.
To determine the force of reaction exerted by the block on the rope, we need to consider the forces acting on the block.
First, let's identify the forces involved:
1. The applied force (A+force) of 12 N, which pulls the block.
2. The force of gravity acting on the block, which can be calculated using the formula Fgravity = m * g, where m is the mass of the block (3.5 kg) and g is the acceleration due to gravity (9.8 m/s²).
3. The force of gravity acting on the rope, which can be calculated using the formula Fgravity = m * g, where m is the mass of the rope (0.5 kg) and g is the acceleration due to gravity (9.8 m/s²).
4. The force of reaction exerted by the block on the rope, which is the force we're trying to find.
Now, let's calculate the forces involved:
1. Force of gravity on the block: Fgravity = m * g = 3.5 kg * 9.8 m/s² = 34.3 N
2. Force of gravity on the rope: Fgravity = m * g = 0.5 kg * 9.8 m/s² = 4.9 N
Since the block is on a frictionless surface, the force of reaction exerted by the block on the rope is equal to the force of gravity acting on the rope. Therefore, the force of reaction exerted by the block on the rope is 4.9 N.