Two cars leave Kansas City at the same time.
One car is moving east and the other west.
After 5 hours, the cars are 575 miles apart.
One car is traveling 15 miles per hour faster than the other.
Let S = the speed of the slower car and F = the speed of the faster car.
If one equation for this system is 5F + 5S = 575, what is the other? Type your answer without spaces.
I don't understand this problme its saying one is 15 mile faster
would'nt it be 15F+60S=575? If it's wrong please tell me what i did wrong and explain it.
So it would be 5s+15s+5s=575?
5F + 5S = 575.
F = S+15.
5(S+15) + 5S = 575.
hint:
5(S+15)=5*S+5*15 (distribution)
=5S+75
In this problem, we need to find the other equation in the system.
Let's assume that the speed of the slower car is S mph. Since the other car is moving 15 mph faster, the speed of the faster car would be S + 15 mph.
We are given that the cars are moving for 5 hours, so we can write the equation:
Distance traveled by the slower car = Speed × Time = S × 5
Distance traveled by the faster car = Speed × Time = (S + 15) × 5
The sum of distances traveled by both cars should equal the total distance between them, which is 575 miles. So, we can write the equation:
5S + 5(S + 15) = 575
Simplifying this equation will give us the other equation in the system. Expanding and combining like terms, we get:
5S + 5S + 75 = 575
10S + 75 = 575
10S = 575 - 75
10S = 500
Dividing both sides of the equation by 10, we find:
S = 50
Therefore, the other equation in the system is:
5F + 5S = 575, where S = 50.
Hope this explanation helps!