For the first tour on Monday, a museum sells 4 child tickets and 8 adult tickets for $128. For the second tour the museum sells 6 adult tickets for $72. Find the price of one child ticket and the price of one adult ticket
Why did the museum tickets go to therapy? Because they couldn't figure out their pricing issues! Let's solve this mystery together, shall we?
Let's assume the price of one child ticket is C dollars, and the price of one adult ticket is A dollars.
For the first tour, the museum sells 4 child tickets and 8 adult tickets for $128. So we can form the equation:
4C + 8A = 128
For the second tour, the museum sells 6 adult tickets for $72. We can form another equation:
6A = 72
Now, let's solve the second equation for A:
A = 72 / 6
A = 12
Now that we know the price of one adult ticket is $12, let's substitute this value into the first equation:
4C + 8(12) = 128
Simplifying:
4C + 96 = 128
4C = 128 - 96
4C = 32
Finally, we can solve for C:
C = 32 / 4
C = 8
So, the price of one child ticket is $8 and the price of one adult ticket is $12. Enjoy your trip to the museum!
To find the price of one child ticket and one adult ticket, we can set up a system of equations using the given information.
Let's assume the price of one child ticket is "c" and the price of one adult ticket is "a".
From the first tour, we know that 4 child tickets and 8 adult tickets were sold for a total of $128. This can be expressed as:
4c + 8a = 128 Equation 1
From the second tour, we know that 6 adult tickets were sold for a total of $72. This can be expressed as:
6a = 72 Equation 2
Now, we can solve this system of equations to find the values of "c" and "a".
From Equation 2, we can divide both sides by 6 to solve for "a":
6a = 72
a = 72/6
a = 12
Now, we can substitute the value of "a" back into Equation 1 to solve for "c":
4c + 8a = 128
4c + 8(12) = 128
4c + 96 = 128
4c = 128 - 96
4c = 32
c = 32/4
c = 8
Therefore, the price of one child ticket is $8 and the price of one adult ticket is $12.
To find the price of one child ticket and the price of one adult ticket, we can set up a system of equations based on the given information.
Let's assume the price of one child ticket is C dollars, and the price of one adult ticket is A dollars.
From the first tour, we know that 4 child tickets and 8 adult tickets were sold for a total of $128. This can be represented by the equation:
4C + 8A = 128 ----(1)
From the second tour, we know that 6 adult tickets were sold for $72. This can be represented by the equation:
6A = 72 ----(2)
Now, we can solve this system of equations:
Let's solve equation (2) for A:
6A = 72
Divide both sides by 6:
A = 12
Now, substitute the value of A (12) into equation (1):
4C + 8(12) = 128
Simplify:
4C + 96 = 128
Subtract 96 from both sides:
4C = 32
Divide both sides by 4:
C = 8
Therefore, the price of one child ticket is $8, and the price of one adult ticket is $12.
mama
C=child ticket
A=adult ticket
4C+8A=128 => C+2A=32...........(1)
6A=72 => A=12.................(2)
Substitute (2) into (1)
C+2(12)=32
solve for C.