PLEASEEEE HELP
Write the balanced equation for the reaction between zinc and acetic acid. The equation has been written you just have to balance.
___Zn + ___HC2H3O2 → ___Zn(CH3COO)2 + ___H2
Sure, here's an attempt at balancing the equation for you:
Zn + 2 HC2H3O2 → Zn(CH3COO)2 + H2
Remember, balancing equations is all about ensuring the same number of atoms of each element are on both sides of the equation. If you have any more chemistry questions or need help with anything else, feel free to ask!
To balance the equation for the reaction between zinc and acetic acid, follow these steps:
1. Count the number of atoms of each element on both sides of the equation.
Left side:
Zinc (Zn) - 1
Hydrogen (H) - 1
Carbon (C) - 2
Oxygen (O) - 2
Right side:
Zinc (Zn) - 1
Hydrogen (H) - 4
Carbon (C) - 4
Oxygen (O) - 2
2. Balance the equation by adjusting the coefficients in front of each compound.
___Zn + ___HC2H3O2 → ___Zn(CH3COO)2 + ___H2
To balance the equation, add coefficients as needed:
1Zn + 2HC2H3O2 → 1Zn(CH3COO)2 + 1H2
Now the equation is balanced, with the same number of atoms on both sides:
1 Zinc + 2 Acetic acid → 1 Zinc acetate + 1 Hydrogen gas
To balance the equation for the reaction between zinc and acetic acid, you need to make sure that the number of atoms of each element is equal on both sides of the equation.
Given:
___Zn + ___HC2H3O2 → ___Zn(CH3COO)2 + ___H2
Let's start balancing the equation step by step:
1. Balance the carbon atoms:
On the left side, there is one carbon atom in acetic acid (HC2H3O2), so we need to have one carbon atom in the product as well. Hence, we put a coefficient of 1 in front of Zn(CH3COO)2:
___Zn + ___HC2H3O2 → 1Zn(CH3COO)2 + ___H2
2. Balance the hydrogen atoms:
On the left side, there are four hydrogen atoms in acetic acid (HC2H3O2), and on the right side, there are two hydrogen atoms in H2. To balance the hydrogen atoms, we need to put a coefficient of 2 in front of H2:
___Zn + ___HC2H3O2 → 1Zn(CH3COO)2 + 2H2
3. Balance the oxygen atoms:
On the left side, there are two oxygen atoms in acetic acid (HC2H3O2), and on the right side, there are four oxygen atoms in Zn(CH3COO)2. To balance the oxygen atoms, we need to put a coefficient of 2 in front of HC2H3O2:
___Zn + 2HC2H3O2 → 1Zn(CH3COO)2 + 2H2
4. Balance the zinc atoms:
On the left side, there is one zinc atom (Zn), so we put a coefficient of 1 in front of Zn:
1Zn + 2HC2H3O2 → 1Zn(CH3COO)2 + 2H2
The final balanced equation for the reaction between zinc and acetic acid is:
Zn + 2HC2H3O2 → Zn(CH3COO)2 + 2H2