Is my answer correct?

Find Pk + 1 if
Pk = 7 + 13 + 19 + ...+[6(k - 1)+1] + (6k + 1)
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7 + 13 + 19 + …+[6(k - 1) + 1] + (6k + 1) + [6(k + 1) + 1]

8 + 14 + 20 + …+[7(k - 1) + 1] + (7k + 1)

7 + 13 + 19 + …+(6k + 1)

7 + 13 + 19 + ...+[6(k - 1) + 1] + (6k +1) + (6k + 2)

answer: d