Math

Brian was training to run a marathon. During the three day period before the race he decided he would train for 11 hours. If he trained for 2 3/5 hours first day and 2 9/10 second day, how many hours would he need to train third day.

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I solved it to the point where I got improper fraction of 13/5 +29/10 then I did
130/50 + 154/50 then I got 275/50 I simplified it to 5/2. The answer is however 5 1/2 I don't know how.

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  1. Take out your calculator, or do it by hand,
    275/50=55/10=5 1/2

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  2. why use 50 for the common denominator, when 10 works just as well?

    13/5 + 29/10
    = 26/10 + 29/10
    = 55/10

    Now subtract that total from the 11 hours (110/10) needed, and you still need 55/10 = 5 1/2

    275/50 is 5 1/2, not 5/2.

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