A median of a number is 5.

A mean is 5.
They're five different numbers.
They're not integers.
Workout the numbers.

Please help me I got a test tomorrow please!:)

if there are five of them and the median is five I think five is an integer

a b c d e

c = 5

(a+b+c+d +e)/5 = 5
so
a+b+5+d+e = 25

a+b+d+e=20
with d and e >5 and a and b <5
well what if
a = 1
b= 2
d= 7
e = 10

1 2 5 7 10

they're not integer!!!!

5 is an integer

I wrote 47.235 as my answer then it asked me to use the calculator to find a complete answer.How I'm I suppose to do this.

please I need help I got a test tomorrow.Thankyou

The set 1 2 5 7 10

has mean=5
median=5

Now, if you don't want integers, then fudge the values a bit.

1.1 2.1 5 6.9 9.9

The mean is still 5.

Since there are an odd number of values, the median must be the center number. If it is 5, then the median is an integer. I see no way to have an integer median for an odd set of non-integer values.

To find the five different numbers with a median of 5 and a mean of 5, we can approach this problem by using algebra. Let's represent the five numbers as a1, a2, a3, a4, and a5.

First, let's consider the mean. The mean is calculated by summing all the numbers and dividing by the total count. In this case, we have:
(a1 + a2 + a3 + a4 + a5) / 5 = 5

Next, let's consider the median. The median is the middle value when the numbers are arranged in ascending order. In this case, since we have five different numbers, the median would be the third number when arranged in ascending order.

To solve this problem, we need to find five different numbers that satisfy both the mean and median conditions. Let's go step by step:

Step 1: Assign variables to the five numbers.
Let a1 be the smallest value, a2 the second smallest, a3 the median (which is 5), a4 the second largest, and a5 the largest.

Step 2: Set up the equation for the mean.
(a1 + a2 + a3 + a4 + a5) / 5 = 5

Step 3: Simplify the equation.
a1 + a2 + a3 + a4 + a5 = 25

Step 4: Use the median condition.
Since the median is 5, a3 = 5.

Step 5: Substitute the values into the equation.
a1 + a2 + 5 + a4 + a5 = 25

Step 6: Rearrange the equation.
a1 + a2 + a4 + a5 = 25 - 5

Step 7: Simplify further.
a1 + a2 + a4 + a5 = 20

At this point, we have three unknowns (a1, a2, a4) but only one equation, which means we have multiple possible solutions. Let's explore one possibility:

Assume a1 = 1.
Then, a2 + a4 + a5 = 19.

Now we need to select two distinct numbers for a2 and a4, such that their sum is 19. Since you mentioned that the numbers are not integers, let's use decimal numbers:

Assume a2 = 7.5.
Then, a4 + a5 = 11.5.

If we let a4 = 6 and a5 = 5.5, we satisfy the condition.

Therefore, one possible set of five numbers that satisfies the given conditions is:
1, 7.5, 5, 6, 5.5.