The height above ground of a snowball thrown from a cliff is modeled by the function h(t) = -16t2 + 64t + 192, where h is height in feet and t is time in seconds.

I d3on't know what to do with this i use to do this but know i forgot
Guide me through this please

a median of a number is 5

a mean is 5
they're five different numbers.
they're not integers.
workout the numbers.

please help me i got a test tommorow please!:)

No problem! I can help you with that.

To find the height above the ground at a given time, you need to substitute the value of "t" into the equation h(t) = -16t^2 + 64t + 192, and then solve for "h". Here's how it's done step-by-step:

Step 1: Identify the given values
In this case, the equation h(t) = -16t^2 + 64t + 192 is already given to you. You'll need the value of "t" to find the corresponding height "h".

Step 2: Substitute the value of "t" into the equation
Let's say you want to find the height at t = 3 seconds. Substitute t = 3 into the equation:
h(3) = -16(3)^2 + 64(3) + 192

Step 3: Simplify the equation
Evaluate the equation from left to right following the order of operations (PEMDAS/BODMAS):
h(3) = -16(9) + 192 + 192
h(3) = -144 + 384
h(3) = 240

Therefore, at t = 3 seconds, the height above the ground is 240 feet.

You can repeat this process for any value of "t" to find the corresponding height. Just substitute the desired value into the equation and simplify.

It's important to note that the equation is a quadratic equation in the form of h(t) = at^2 + bt + c, where "a" is -16, "b" is 64, and "c" is 192. This equation represents the height of a snowball thrown from a cliff using the laws of motion.

I hope this explanation helps you understand how to use the given equation to find the height above the ground at a given time! Let me know if you have any further questions.