Two forces act on an object. one has a magnitude of 4N in the y axis and the other has a 4N and is pointing 30 degrees below the posive x axis. what is the magnitude of the net force acting on the object?

<0,4> + <3.46,-2> = <3.46,2> = 4N 30 degrees above the x-axis.

Makes sense. Since the two vectors are the same magnitude, and 120 degrees apart, their resultant will be 60 degrees from each.

To find the magnitude of the net force acting on the object, we first need to find the vector sum of the two forces.

Let's break down the forces into their x and y-components:

Force 1: 4N in the y-axis = 0N in the x-axis and 4N in the y-axis

Force 2: 4N at a 30-degree angle below the positive x-axis

To find the components of Force 2, we can use trigonometry. The x-component can be found by multiplying the magnitude of the force (4N) by the cosine of the angle (30 degrees), while the y-component can be found by multiplying the magnitude of the force (4N) by the sine of the angle (30 degrees).

x-component of Force 2 = 4N × cos(30°) = 4N × (√3/2) = 2√3 N
y-component of Force 2 = 4N × sin(30°) = 4N × (1/2) = 2N

Now, we can sum up the x and y-components of the forces separately:

x-component of the net force = 0N + 2√3 N = 2√3 N
y-component of the net force = 4N + 2N = 6N

To find the magnitude of the net force, we can use the Pythagorean theorem. The magnitude (F) is given by:

F = √((x-component)^2 + (y-component)^2)
= √((2√3 N)^2 + (6N)^2)
= √(12N^2 + 36N^2)
= √(48N^2)
= √(16 × 3N^2)
= 4√3 N

Therefore, the magnitude of the net force acting on the object is 4√3 N.