((2)/(x-2))^(2)-3((2)/(x-2))+2=0
please explain the steps!
If you want to solve it, then let u=2/(x-2). Then you have
u^2-3u+2=0
(u-2)(u-1) = 0
so, u=1 or u=2
Substitute that back for x and then you can find the solutions.
please explain the steps!
u^2-3u+2=0
(u-2)(u-1) = 0
so, u=1 or u=2
Substitute that back for x and then you can find the solutions.