A 1000 kg car is initially at rest. If the motor does 10,000J of work on the car, what is the car’s final speed? (Neglect friction, and assume that the car is on level ground.)

To determine the car's final speed, we can use the work-energy principle, which states that the work done on an object is equal to the change in its kinetic energy.

First, we need to calculate the change in kinetic energy of the car. The formula for kinetic energy is KE = 1/2 * mass * velocity^2.

Since the car is initially at rest, its initial kinetic energy (KEi) is zero. Therefore, the change in kinetic energy (ΔKE) is equal to the final kinetic energy (KEf).

Now, let's calculate the change in kinetic energy.

ΔKE = KEf - KEi

Since KEi = 0, we can simplify the equation to be ΔKE = KEf.

We know that the work done on the car (W) is equal to the change in kinetic energy:

W = ΔKE

Substituting the formula for kinetic energy, we have:

W = 1/2 * mass * velocity^2

Rearranging the formula to solve for velocity:

velocity^2 = (2 * W) / mass

Let's plug in the given values:

mass = 1000 kg
W = 10,000 J

velocity^2 = (2 * 10,000 J) / 1000 kg

velocity^2 = 20 m^2/s^2

Taking the square root of both sides, we find:

velocity = √20 m/s ≈ 4.47 m/s

Therefore, the car's final speed is approximately 4.47 m/s.

Work = KE2-KE1 = KE2-0 = KE2.

KE2 = 0.5M*V^2 = 10,000 J.
500*V^2 = 10,000, V = ?.