What is the concentration of Pb in mg/L , if you have 25 mg Pb in 5kg of seawater? (note: density of seawater is 1.025 kg/L)
Again, I assume this is ppm w/v.
Volume of 25 kg seawater is
v = m/d = 5000 g/1.025 g/mL = 4878 mL. Then mg Pb/L = ? mg/L = ppm w/v
Thank you!
To determine the concentration of Pb in mg/L, we need to convert the given data into the appropriate units and calculate the concentration.
1. Convert the mass of seawater from kg to L: Given that the density of seawater is 1.025 kg/L, we can determine the volume of 5 kg of seawater by dividing the mass by the density.
Volume of seawater = mass of seawater / density of seawater = 5 kg / 1.025 kg/L
2. Calculate the concentration of Pb in mg/L: Divide the mass of Pb (given as 25 mg) by the volume of seawater calculated in the previous step.
Concentration of Pb = mass of Pb / volume of seawater
Let's calculate the concentration of Pb using these steps:
Step 1:
Volume of seawater = 5 kg / 1.025 kg/L = 4.878 L (rounded to three decimal places)
Step 2:
Concentration of Pb = 25 mg / 4.878 L = 5.127 mg/L (rounded to three decimal places)
Therefore, the concentration of Pb in the seawater is approximately 5.127 mg/L.