Name two ways to solve for y=2x^2+16
complete the square
quadratic formula
After it says choose the correct solution(s)
x=-8
x= plus or minus square root of 8
x= plus or minus2isquareroot of 2
x= plus or minus8i
so, did you apply one of the methods?
recall that
(a+bi)(a-bi) = a^2+b^2
HOw do i apply quadratic if there isnt a b
there is always a b. In this case, it is zero!
2x^2+16 = 0
2(x^2+8) = 0
2(x+√8 i)(x-√8 i) = 0
...
I got 4i square root of 8 over 4
So is the answer c
To solve the equation y = 2x^2 + 16, there are two common ways you can use:
1. Algebraic Method:
Step 1: Start with the equation y = 2x^2 + 16.
Step 2: Set y equal to zero by subtracting y from both sides, 2x^2 + 16 = 0.
Step 3: Subtract 16 from both sides, 2x^2 = -16.
Step 4: Divide both sides by 2 to isolate x^2, x^2 = -8.
Step 5: Take the square root of both sides, considering both positive and negative roots, x = ± √(-8).
Step 6: Simplify the square root expression further, x = ± √(8i), where i represents the imaginary unit (√(-1)).
Step 7: So, the solution for x is x = ± √(8i).
Step 8: Substitute the obtained values for x back into the original equation to solve for y.
2. Graphical Method:
Step 1: Plot the graph of the equation y = 2x^2 + 16 on a graphing tool or software.
Step 2: Find the points where the graph intersects or touches the x-axis.
Step 3: The x-coordinates of these points are the solutions to the equation.
Step 4: Read the corresponding y-values at those x-coordinates to get the value of y.
Note: In this case, since the coefficient of x^2 is positive (2 > 0), the graph will be an upward-opening parabola.