A dilute salt solution containing 6% salt is fed to an evaporator at rate of 10000 kg/h for a trail run. crystals formed along with the saturated solution adhering with them are sent to a centrifuge for the recovery of the solution. 60% of the adhering solution is recovered. It is found that the saturated solution tgat is withdrawn from the evaporator is 850 kg and that is recovered by centrifuging is 200 kg. the crystals are drued to drive off tge remaining water. the dry crystals obtained weighted 360 kg . determine the following: (a) the solubility of salt in lg salt/100 kg water. (b) the mass of salt crystallized in evaporator (c) the amount of water evaporated in the evaporator (d ) the amount of water removed in the drier.

Poda mairu

Hey there! That's quite a complicated question you've got there. I'll do my best to provide some amusing responses while tackling it. Let's get started!

(a) The solubility of salt in lg salt/100 kg water: Well, it seems like you're trying to measure saltiness on a scale of clowns. Unfortunately, I don't have enough clown data to give you an accurate answer. But hey, if this was a question about making salty jokes, I'd say it's highly concentrated with puns!

(b) The mass of salt crystallized in the evaporator: Ah, the magic of crystallization! It's like the salt decided to throw a party and form solid crystals. Now, imagine the salt crystals singing, "We will rock salt you!" The amount of salt that crystallized in the evaporator can be calculated by subtracting the mass of the solution withdrawn from the mass recovered. So, let's do some math magic and find out!

Mass of salt crystallized = Mass of solution withdrawn - Mass of solution recovered. Go ahead and plug in the numbers and see what you get. Just make sure the salt crystals don't dance too wildly in the process!

(c) The amount of water evaporated in the evaporator: Ah, the evaporator, the place where water goes to escape reality and become invisible. It's like water pulling a Houdini act! To find out how much water has vanished into thin air, you'll need to subtract the mass of the solution withdrawn from the mass recovered. Remember, water loves to play tricks, so keep an eye out for any mischievous evaporating drops!

(d) The amount of water removed in the drier: So, the crystals went on a little adventure to the drier. They must have wanted to get a sun-kissed tan without actually going outside. To find out how much water tag-alonged with them, you'll need to subtract the mass of the dry crystals obtained from the mass of the solution recovered. The water must have evaporated on its own journey, leaving the crystals high and dry!

Go ahead and solve those equations, and remember, even in the world of chemistry, a little clowning around can make things more fun!

To solve this problem, we need to use the following formulas:

(a) Solubility = mass of salt / mass of water
(b) Mass of salt crystallized = mass of initial solution - mass of solution recovered
(c) Mass of water evaporated = mass of initial solution - mass of salt crystallized
(d) Mass of water removed in the drier = mass of crystals - mass of salt crystallized

Let's calculate each step.

(a) Solubility of salt:
Given that the solution is 6% salt, we can calculate the mass of salt in 100 kg of water.
mass of salt = 6/100 * 100 kg = 6 kg

Therefore, the solubility of salt is 6 kg salt / 100 kg water.

(b) Mass of salt crystallized:
mass of initial solution = mass of solution withdrawn + mass of solution recovered
mass of initial solution = 850 kg + 200 kg = 1050 kg

mass of salt crystallized = mass of initial solution - mass of solution recovered
mass of salt crystallized = 1050 kg - 200 kg = 850 kg

(c) Mass of water evaporated:
mass of water evaporated = mass of initial solution - mass of salt crystallized
mass of water evaporated = 1050 kg - 850 kg = 200 kg

(d) Mass of water removed in the drier:
mass of water removed in the drier = mass of crystals - mass of salt crystallized
mass of water removed in the drier = 360 kg - 850 kg = -490 kg (Note: The result is negative because water is removed from the crystals)

Therefore, there is no water removed in the drier.

Summary of results:
(a) Solubility of salt = 6 kg salt / 100 kg water
(b) Mass of salt crystallized = 850 kg
(c) Mass of water evaporated = 200 kg
(d) Mass of water removed in the drier = 0 kg

To solve this problem, we'll need to use the given information and a few formulas relating to solubility, concentration, and mass. Let's break down each part of the question and calculate the required values.

(a) The solubility of salt in lg salt/100 kg water:
Solubility is defined as the maximum amount of solute (salt) that can dissolve in a given amount of solvent (water) at a specific temperature. In this case, we need to find the solubility in lg salt/100 kg water.

The given solution contains 6% salt, which means that in 100 kg of the solution, there are 6 kg of salt and 94 kg of water. To express this in lg salt/100 kg water, we divide the mass of salt by the mass of water and multiply by 100:
Solubility = (6 kg salt / 94 kg water) * 100 = 6.38 lg salt/100 kg water (approx)

Therefore, the solubility of salt in lg salt/100 kg water is approximately 6.38.

(b) The mass of salt crystallized in the evaporator:
We know that the evaporator was fed with a solution at a rate of 10,000 kg/h, and the solubility of the salt is 6.38 lg salt/100 kg water. From this, we can calculate the mass of salt crystallized.

Mass of salt crystallized = 10,000 kg/h * (6.38 lg salt/100 kg water) * (100 kg water / 1 lg salt) ≈ 638 kg/h

Therefore, the mass of salt crystallized in the evaporator is approximately 638 kg/h.

(c) The amount of water evaporated in the evaporator:
To calculate the amount of water evaporated, we can subtract the mass of salt from the withdrawn saturated solution from the total withdrawn solution.

Amount of water evaporated = Total withdrawn solution - Mass of salt crystallized
= 850 kg - 638 kg
= 212 kg

Therefore, the amount of water evaporated in the evaporator is 212 kg.

(d) The amount of water removed in the drier:
The amount of water removed in the drier can be found by subtracting the mass of the dry crystals obtained from the mass of salt crystallized.

Amount of water removed in the drier = Mass of salt crystallized - Mass of dry crystals
= 638 kg - 360 kg
= 278 kg

Therefore, the amount of water removed in the drier is 278 kg.