A watermelon is dropped from the top of a building The height of the watermelon above the sidewalk is given by h(t)=-16t^2+240 with t representing number of seconds
How many seconds does it take for the watermelon to hit the sidewalk
h(t) = 240 - 16tT^2 = 0.
16t^2 = 240, t = 3.87 s.
6
To find the number of seconds it takes for the watermelon to hit the sidewalk, we need to find the value of t when h(t) = 0.
Given:
h(t) = -16t^2 + 240
Setting h(t) equal to zero and solving for t:
0 = -16t^2 + 240
Rearranging the equation:
16t^2 = 240
Dividing both sides by 16:
t^2 = 15
Taking the square root of both sides:
t = √15
Therefore, it takes approximately √15 seconds for the watermelon to hit the sidewalk.
To find the number of seconds it takes for the watermelon to hit the sidewalk, we need to find the value of t when the height of the watermelon (h(t)) is equal to zero.
Given the equation for the height of the watermelon above the sidewalk:
h(t) = -16t^2 + 240
We set h(t) equal to zero and solve for t:
-16t^2 + 240 = 0
Next, let's solve for t by factoring out the greatest common factor (GCF) from the equation:
-16(t^2 - 15) = 0
Setting each factor equal to zero:
-16 = 0 (This is not possible)
t^2 - 15 = 0
Now, solve for t using the quadratic formula:
t^2 - 15 = 0
t^2 = 15
Applying the square root to both sides:
t = ± √15
Since time cannot be negative in this context, we take the positive value of the square root:
t ≈ √15
Therefore, it takes approximately √15 seconds for the watermelon to hit the sidewalk.