a ball is dropped from a 50 meter cliff and its height h above the ground at any time ti is given by thte equation h(t)=50-4.9t^2

What is your question?

How long is the ball in the air before it hits the ground

well, what is h when it hits the ground? ...

To determine the height of the ball at any given time, we can use the equation h(t) = 50 - 4.9t^2. Let's go through the steps to find the height at a specific time.

1. Identify the given time value, t.
2. Substitute the value of t into the equation h(t) = 50 - 4.9t^2.
3. Square the value of t.
4. Multiply the squared value by 4.9.
5. Subtract the result from 50 to find the height.

For example, let's say we want to find the height of the ball 2 seconds after it was dropped.

1. Given time value, t = 2 seconds.
2. Substitute t into the equation: h(t) = 50 - 4.9(2^2).
3. Square the value of 2: 2^2 = 4.
4. Multiply the squared value by 4.9: 4.9 * 4 = 19.6.
5. Subtract the result from 50: 50 - 19.6 = 30.4.

Therefore, the height of the ball 2 seconds after being dropped from a 50-meter cliff is 30.4 meters.