What is the 5th of 9 consecutive whole numbers whose sum is 153 is what?
sum(9) = (9/2)(2a + 8d) = 153
times 2
9(2a + 8d) = 306
18a + 72d = 306
divide by 18
a + 4d = 17
term(5) = a+4d = 17 from above
To find the 5th of 9 consecutive whole numbers whose sum is 153, we need to determine the value of each individual number.
Let's denote the first number as "x". Since we have 9 consecutive whole numbers, the other numbers can be represented as x+1, x+2, x+3, x+4, x+5, x+6, x+7, x+8.
The sum of these numbers can be expressed as:
x + (x+1) + (x+2) + (x+3) + (x+4) + (x+5) + (x+6) + (x+7) + (x+8) = 153
To solve this equation, we can combine like terms:
9x + 36 = 153
Next, subtract 36 from both sides of the equation:
9x = 117
Then, divide both sides by 9 to solve for x:
x = 13
Now that we know the value of x, we can find the 5th number:
x + 4 = 13 + 4 = 17
Therefore, the 5th of the 9 consecutive whole numbers whose sum is 153 is 17.