I am trying to factor a 4th degree polynomial that does not have any rational roots. I need to somehow get it factored into two quadratics. Anyone know of a method to use. 3x^4 - 8x^3 - 5x^2 + 16x - 5 Two of the irrational roots
if a quadratic equation with real coefficents has a discriminant of 10, then what type of roots does it have? A-2 real, rational roots B-2 real, irrational roots C-1 real, irrational roots D-2 imaginary roots
Could someone please check the first one and help me with the second one. I'm stuck-Thank you 1.What are theroots of the following polynomial equation? (x+2i)(x-5)(x-2i)(x+8) = 0 I think the roots are -2i,5,2i,-8-you take out the
Let f(x)= px^5 + qx^4 + rx^3 + sx^2 + tx + u be a polynomial such that f(1) = -1 and f(2) = 3 and all the numbers p, q, r, s, t and u are integers. prove that the equation px^5 + qx^4 + rx^3 + sx^2 + tx + u = 0 has no integer
1) Find the roots of the polynomial equation. x^3-2x^2+10x+136=0 2) Use the rational root theorem to list all problem rational roots of the polynomial equation. x^3+x^2-7x-4=0. Do not find the actual roots.
Suppose the polynomial f(x) has the following roots: 1+6sqrt2, 2−sqrt6, and 6+sqrt2. If f(x) has only rational coefficients, the Irrational Root Theorem indicates that f(x) has at least three more roots. What are the three
if f (x) is a polynomial of degree 3 whose roots are p,q,r. FIND f (3) if sum of cubes of roots is 0 and sum of squares of roots and sum of roots are unit digit of 3^2018 and 5^50666666666 respectively?
Suppose a and b are positive integers satisfying 1≤a≤31, 1≤b≤31 such that the polynomial P(x)=x^3−ax^2+a^2b^3x+9a^2b^2 has roots r, s, and t. Given that there exists a positive integer k such that (r+s)(s+t)(r+t)=k^2,