Write a Balanced equation for the chemcial reaction Acetylene gas (C2H2) burns in a welding torch with oxygen to form carbon dioxide gas and water vapor.
C2H2(g) + O2(g) ==> CO2(g) + H2O(g)
It isn't balanced. I will leave that for you.
How do i balance it?
trial and error.
C2H2 + O2 ==> CO2 + H2O.
I see 2 C on the left and only 1 on the right so I place a coefficient of 2 for CO2 on the right. And we go from there. Sometimes the 2 is right and sometimes it must be changed. So we are up to
C2H2 + O2 ==> 2CO2 + H2O
Now you finish.
Okay,is this right?
2 C2H2 + 5 O2 --> 4 CO2 + 2 H2O
Very good.
Well done! That's a balanced equation. You've got the right amount of carbon, hydrogen, and oxygen on both sides. Give yourself a pat on the back! Now you're ready to set things on fire... safely, of course!
Yes, that is the balanced equation for the chemical reaction between acetylene gas and oxygen to form carbon dioxide gas and water vapor. Well done!
Yes, your balanced equation is correct:
2 C2H2 + 5 O2 --> 4 CO2 + 2 H2O
To balance the equation, you need to ensure that the number of atoms of each element is the same on both sides of the equation. Here's how you can do it:
1. Start by counting the number of each type of atom on each side of the equation.
- On the left side, you have 2 C atoms and 4 H atoms from C2H2, and 5 O atoms from O2.
- On the right side, you have 4 C atoms from CO2 and 2 H atoms from H2O.
2. Begin by balancing the carbon atoms. Since there are 2 C atoms on the left side, you place a coefficient of 2 in front of CO2 on the right side.
C2H2 + O2 --> 2 CO2 + H2O
3. Next, balance the hydrogen atoms. There are already 2 H atoms on the right side, so no changes are needed.
C2H2 + O2 --> 2 CO2 + 2 H2O
4. Finally, balance the oxygen atoms. You have 5 O atoms on the right side and only 2 O atoms on the left side, so you place a coefficient of 5/2 (or 2.5) in front of O2 on the left side.
2.5 C2H2 + O2 --> 2 CO2 + 2 H2O
However, it is not recommended to have fractional coefficients in a balanced equation, so we multiply the entire equation by 2 to eliminate the fractional coefficients.
5 C2H2 + 2 O2 --> 4 CO2 + 4 H2O
This equation is balanced and represents the chemical reaction for the combustion of acetylene gas with oxygen in a welding torch.