1.63 L of an aqueous solution containing 25.00g of KCl dissolved in pure water is prepared. The molarity of the solution is?
Molarity=moles/liter=(25/molmass)/1.63
figure out the formula mass of KCl, and you have it.
To find the molarity of a solution, you need to know the number of moles of solute (KCl) and the volume of the solution in liters.
First, let's calculate the number of moles of KCl. The molar mass of KCl is the sum of the atomic masses of potassium (K) and chlorine (Cl). The atomic mass of K is 39.10 g/mol, and the atomic mass of Cl is 35.45 g/mol.
The molar mass of KCl = 39.10 g/mol + 35.45 g/mol = 74.55 g/mol
Now, we can calculate the number of moles of KCl using the given mass:
Number of moles = Mass of KCl / Molar mass of KCl
= 25.00 g / 74.55 g/mol
Next, let's calculate the volume of the solution in liters. The given volume is 1.63 L.
Now, we can calculate the molarity using the formula:
Molarity (M) = Number of moles / Volume of solution in liters
Substituting the values we have calculated:
Molarity (M) = (25.00 g / 74.55 g/mol) / 1.63 L
Please calculate and simplify the equation to determine the molarity.