How many grams of water and how many grams of 85 wt% phosphoric acid would be needed to make 100 grams of 37 wt% phosphoric acid solution?
in the 100 g of 37wt, then you need
100*.37 grams of phosphoric acid (pure).
So you need then of 85percent, 100*.37/.85 grams of the 85 percent phosphoric acid, and of water the remainder 100(1-.37/.85) grams of water Near 56 grams water).
To determine how many grams of water and grams of 85% phosphoric acid are needed to make 100 grams of a 37% phosphoric acid solution, we need to apply the concept of mass percent and perform a simple calculation.
Let's break down the problem step by step:
Step 1: Identify the given information:
- Target solution weight: 100 grams
- Target phosphoric acid concentration: 37 wt%
- Concentration of the available phosphoric acid solution: 85 wt%
Step 2: Calculate the weight of phosphoric acid in the target solution:
To find the weight of phosphoric acid required in the 37% solution, you can use the following formula:
Weight of phosphoric acid = (Target concentration / Total concentration) * Target solution weight
Weight of phosphoric acid = (37 wt% / 100 wt%) * 100 grams
Weight of phosphoric acid = 37 grams
Step 3: Calculate the weight of water required:
To determine the weight of water, subtract the weight of phosphoric acid from the total target solution weight:
Weight of water = Target solution weight - Weight of phosphoric acid
Weight of water = 100 grams - 37 grams
Weight of water = 63 grams
Therefore, to make 100 grams of a 37% phosphoric acid solution, you would need 63 grams of water and 37 grams of 85% phosphoric acid.