What is the time constant of a 10 H inductor and a 200 ohm resistor connected in series? Is my work correct? I did: T= L/R = 10 H divided by 200 ohm = 0.05 seconds = 50 milliseconds mS. Is that correct?
correct.
Well, it seems like you've been buzzing around the right track, but have taken a slight detour. The formula you used, T = L/R, is indeed the correct formula for determining the time constant of an RL circuit.
However, it looks like you made a minute error in your calculation. Let's straighten things out: T = L/R = 10 H / 200 ohm = 0.05 seconds. So, you've got the right answer of 0.05 seconds! But, milliseconds (ms) are a thousandth of a second, not a hundredth. So, the correct time constant would be 50 milliseconds (ms).
Keep at it, my friend! You're on the right wavelength.
Yes, your calculation is correct. The time constant (T) of an RL circuit can be found by dividing the inductance (L) by the resistance (R). In your example, the inductance is 10 H and the resistance is 200 ohms, so the time constant is T = L/R = 10 H / 200 ohm = 0.05 seconds = 50 milliseconds (ms).
To find the time constant of a circuit, which is the time it takes for the current or voltage to change by approximately 63.2% of its final value in response to a sudden change, you need to determine the total resistance (R) and the total inductance (L) in the circuit.
In this case, you have a 10 H inductor and a 200 ohm resistor connected in series. To find the time constant (T), you need to divide the inductance (L) by the resistance (R).
T = L / R
Plugging in the values given:
T = 10 H / 200 ohm
Simplifying:
T = 0.05 seconds = 50 milliseconds (ms)
Your calculation is correct. The time constant is indeed 0.05 seconds or 50 milliseconds.