Triangle DEF with vertices D(2,5), E(1,-6), and F(-5,3) is translated 3 units right and 2 units down. Find the coordiantes of DEF.

(x,y)

MOVE LEFT : Subtract however many units left you go from x

MOVE RIGHT: Add however many units right you go to x

MOVE UP: Add however many units up you go to y

MOVE DOWN: Subtract however many units down you go from y

^ Do that for all 3 vertices ( D, E, and F)

I still do no tget it?

To find the new coordinates of the triangle DEF after the translation, you need to add the translation vector to each vertex of the original triangle.

Given that the translation is 3 units to the right and 2 units down, the translation vector is (3, -2).

To find the coordinates of D', the new position of point D, add the translation vector to the original coordinates of D:
xD' = xD + 3
yD' = yD - 2

Plugging in the coordinates of D, which are D(2,5), we get:
xD' = 2 + 3 = 5
yD' = 5 - 2 = 3

So, the coordinates of D' are (5, 3).

Similarly, for the other two vertices:
xE' = xE + 3
yE' = yE - 2

Plugging in the coordinates of E, which are E(1, -6), we get:
xE' = 1 + 3 = 4
yE' = -6 - 2 = -8

So, the coordinates of E' are (4, -8).

For point F:
xF' = xF + 3
yF' = yF - 2

Plugging in the coordinates of F, which are F(-5, 3), we get:
xF' = -5 + 3 = -2
yF' = 3 - 2 = 1

So, the coordinates of F' are (-2, 1).

Therefore, the new coordinates of triangle DEF after the translation are:
D'(5, 3), E'(4, -8), and F'(-2, 1).