Consider the reaction: Fe2O3+2Al=Al2O3
How many kg of Al2O3 are produced from 25.2 kg of Fe2O3 assuming there is sufficient Al?
Fe2O3 + 2Al = Al2O3 + 2Fe
mols Fe2O3 ==> grams/molar mass = ?
Using the coefficients in the balanced equation, convert mols Fe2O3 to mols Al2O3.
Now convert mols Al2O3 to grams Al2O3. g = mols x molar mass = ?
To solve this problem, we first need to determine the molar masses of Fe2O3 and Al2O3.
The molar mass of Fe2O3 can be calculated as follows:
Fe: 55.85 g/mol
O: 16.00 g/mol (3 atoms)
Molar mass of Fe2O3 = (2 * 55.85 g/mol) + (3 * 16.00 g/mol) = 159.70 g/mol
The molar mass of Al2O3 can be calculated as follows:
Al: 26.98 g/mol (2 atoms)
O: 16.00 g/mol (3 atoms)
Molar mass of Al2O3 = (2 * 26.98 g/mol) + (3 * 16.00 g/mol) = 101.96 g/mol
Now, we can calculate the moles of Fe2O3 and then use the mole ratio to determine the moles of Al2O3 produced.
Moles of Fe2O3 = mass of Fe2O3 / molar mass of Fe2O3
Moles of Fe2O3 = 25.2 kg / (159.70 g/mol) = 157.744 mol
According to the balanced equation, the mole ratio between Fe2O3 and Al2O3 is 1:1. This means that for every 1 mole of Fe2O3, 1 mole of Al2O3 is produced.
Moles of Al2O3 = moles of Fe2O3 = 157.744 mol
Finally, we can calculate the mass of Al2O3 produced using the moles of Al2O3 and its molar mass.
Mass of Al2O3 = moles of Al2O3 * molar mass of Al2O3
Mass of Al2O3 = 157.744 mol * (101.96 g/mol) = 16083.022 kg
Therefore, approximately 16,083.022 kg of Al2O3 will be produced from 25.2 kg of Fe2O3, assuming there is sufficient Al.
To determine the amount of Al2O3 produced from 25.2 kg of Fe2O3, we need to use stoichiometry and the molar ratios from the balanced chemical equation.
First, let's calculate the molar mass of Fe2O3 and Al2O3. The molar mass of Fe2O3 is 159.69 g/mol, and the molar mass of Al2O3 is 101.96 g/mol.
Next, we need to find the moles of Fe2O3. We can do this by dividing the mass by the molar mass:
moles of Fe2O3 = mass / molar mass = 25.2 kg * (1000 g/kg) / 159.69 g/mol
Now, let's use the balanced chemical equation to determine the mole ratio between Fe2O3 and Al2O3. From the equation, we can see that 1 mole of Fe2O3 reacts with 1 mole of Al2O3.
Since we have the moles of Fe2O3 and the mole ratio, we can calculate the moles of Al2O3 produced:
moles of Al2O3 = moles of Fe2O3 * (1 mole Al2O3 / 1 mole Fe2O3)
Finally, we can find the mass of Al2O3 produced by multiplying the moles of Al2O3 by the molar mass:
mass of Al2O3 = moles of Al2O3 * molar mass = moles of Al2O3 * 101.96 g/mol
So, to find the mass of Al2O3 produced from 25.2 kg of Fe2O3, you would follow these steps:
1. Calculate the moles of Fe2O3:
moles of Fe2O3 = 25.2 kg * (1000 g/kg) / 159.69 g/mol
2. Use the balanced chemical equation to determine the mole ratio between Fe2O3 and Al2O3:
moles of Al2O3 = moles of Fe2O3 * (1 mole Al2O3 / 1 mole Fe2O3)
3. Calculate the mass of Al2O3 produced:
mass of Al2O3 = moles of Al2O3 * molar mass = moles of Al2O3 * 101.96 g/mol
By following these steps and plugging in the appropriate values, you can find the mass of Al2O3 produced from 25.2 kg of Fe2O3.