I don't understand how I would know what would happen if it collided or bounced, etc. How do I solve a question like this? Suppose the total momentum of two masses before collision is 100kg m/s. What is the total momentum of the two masses after they collide?
0 kg m/s
50 k m/s
100 kg m/s
200 kg m/s
1.100 kg m/s
2.100 kg m/s
3.When there is more mass, there is more inertia
4.The jellyfish will move forward
5.a 61 kg zebra running at 8.0 m/s
6.3N
7.It has a high amount of inertia
8.The total momentum after the collision is the same momentum before the collision
You welcome :) -)_(-
1.C
2.D
3.C
4.A
5.D
6.B
7.C
8.A
100% Connexus students!! (Momentum Quiz)
Hope this helps!
There is one thing you can really count on, Newton's First Law.
If there is no external force on a system, the momentum remains CONSTANT
Momentum before = Momentum after. If I could underline that PERIOD I would do so.
You can not count on mechanical energy being the same before and after.It could be turned into heat or radiation or whatever. You can use energy before and after only if the collision is elastic. However you can bet on Momentum every time.
Momentum after = Momentum before. Even when you get to relativity !
To solve this question, you need to apply the principle of conservation of momentum. According to this principle, the total momentum of an isolated system remains constant before and after a collision.
In this case, the total momentum before the collision is given as 100 kg m/s. Let's say mass 1 has a momentum of p1 kg m/s and mass 2 has a momentum of p2 kg m/s.
After the collision, the masses will either stick together (completely inelastic collision) or bounce off each other (slightly elastic or perfectly elastic collision). Since the problem doesn't specify the type of collision, we'll consider both cases separately.
Case 1: In a completely inelastic collision, the two masses stick together and move as a single unit after the collision. In this case, the total momentum after the collision is simply the sum of the individual momenta before the collision: p_total = p1 + p2 = 100 kg m/s.
Case 2: In a slightly elastic or perfectly elastic collision, the two masses bounce off each other, and their momenta change. The equation for conservation of momentum in this case is: p1_initial + p2_initial = p1_final + p2_final.
Since the problem only provides the total momentum before the collision (100 kg m/s) and not the individual momenta, we cannot determine the exact total momentum after the collision.
Therefore, the correct answer to this question is: The total momentum of the two masses after they collide would depend on the type of collision (completely inelastic or slightly elastic/perfectly elastic) and the individual momenta of the masses before the collision, which are not given in this question. So, we cannot determine the total momentum after the collision based on the information provided.