An educational diagram showcasing two primary electrical setups. In the first diagram, visualize four elongated straight symbols representing 20-ohm resistors aligned parallel to each other, all connected to a labeled '20V emf device' indicated by a circle with +/- polarity symbols. The layout gives a sense that all four resistors share the same power source. The second diagram should depict the same 20-ohm resistors, this time connected in series, one after the other in a simple loop with the '20V emf device'. The format should communicate that the voltage is split evenly among the resistors in the series circuit.

Thanks for any help :)

Four 20 ohm resistors are connected in parallel and the combination is connected to a 20V emf device. The current is:
A) 0.25A
B) 1.0 A
C) 4.0 A
D) 5.0 A
E) 100 E

Parallel circuits:
I know that the voltage is 20V and the Resistance is 20 V. So, I divided I=V/R
I= (20/20)=1 The current for a parallel circuit is found by I= I + I+ I+I
The current is 1 so therefore I total would be 4 or C.

Four 20 ohm resistors are connected in series and the combination is connected to a 20V emf device. The potential difference across any one of the resistors is:
A) 1 V
B) 4 V
C) 5 V
D) 20V
E) 80 V

So there are four resistors that are 20 ohms. Their connected to a 20 V device. The question wants to known volts. Its says for a parallel circuit. I just dividied 20V/4 and got 5V.Is that ok to think of it that way?

Thank you

correct on the first. However, if the second circuit is parallel, each resistor has 20V across it.

For parallel circuit the formula is:

1/Req= 1/Rn....
And there are 4 resistors of 20
So
1/Req= 1/20+1/20+1/20+1/20
1/Req= 4/20
Req/1= 20/4= 5
For the current formula is:
I=V/R
V= 20 given
I= 20/5= 4 so the answer is 4

Well, well, well, look who's back with more circuits! You really have a spark for this stuff, don't you?

Let's tackle the first question. You're absolutely right, my electrifying friend! In a parallel circuit, the voltage across each resistor is the same. So, if we have four 20 ohm resistors connected in parallel and a 20V emf device, each resistor will have the full 20V across it. Now, for some math: 20V divided by 4 resistors gives us 5V. So, the potential difference across any one of the resistors is a shocking 5V! C'mon, that's a shocking pun right there!

Now, onto the second question. You've got a series circuit this time, my current-slaying friend. In a series circuit, the total voltage across the circuit is divided among the resistors. Since you have four 20 ohm resistors and a 20V emf device, we can say that each resistor gets an equal share of the voltage. So, the potential difference across each resistor would be 20V divided by 4, which is a hair-raising 5V. Looks like you're striking gold on this one too, my electrified accomplice!

Keep up the electrifying work, and remember, if you ever need a jolt of humor, I'm here to lighten up your circuits!

For the first question, you correctly identified that the resistors are connected in parallel and the voltage across the circuit is 20V. Using Ohm's Law, you calculated the total current as 1A. Therefore, the correct answer is C) 4.0A, as the current in a parallel circuit is divided among the branches.

For the second question, it is stated that the resistors are connected in series. In a series circuit, the total resistance is the sum of the individual resistances. Since there are four 20 ohm resistors in series, the total resistance is 20 + 20 + 20 + 20 = 80 ohms.

To find the potential difference across any one of the resistors, you can use Ohm's Law (V = IR), where V is the potential difference, I is the current, and R is the resistance. In this case, the current is not given, but it can be calculated using the formula I = V/R. Since the voltage across the circuit is 20V and the total resistance is 80 ohms, the current is 20V / 80 ohms = 0.25A.

Since the resistors are connected in series, the same current flows through all of them. Therefore, the potential difference across any one of the resistors is 0.25A * 20 ohms = 5V. Thus, the correct answer is C) 5V.

You're on the right track with your approach to finding the current in the first scenario, where four 20 ohm resistors are connected in parallel. Using Ohm's Law, which states that current (I) is equal to voltage (V) divided by resistance (R), you correctly calculated that the current in each resistor is 1A (20V / 20 ohms = 1A). Since the resistors are connected in parallel, the total current is the sum of the individual currents, so the total current is 4A (1A + 1A + 1A + 1A = 4A). Therefore, the correct answer is C) 4.0A.

Now let's consider the second scenario where four 20 ohm resistors are connected in series. In a series circuit, the current is the same through each component. Since the resistor values are all the same and they are connected in series, the total resistance for the combination is the sum of the individual resistances. So, 20 ohm + 20 ohm + 20 ohm + 20 ohm = 80 ohms total resistance.

To find the potential difference (voltage) across any one of the resistors, we can use Ohm's Law again. In a series circuit, the total voltage across the combination of resistors is equal to the sum of the potential differences across each individual resistor. Since the combination is connected to a 20V emf device, the potential difference across the combination is 20V.

Since all resistors are the same in value and connected in series, the potential difference across any one of the resistors is equal to the total potential difference divided by the number of resistors. Therefore, the potential difference across each resistor is 20V / 4 = 5V. So, the correct answer is C) 5V.

I hope this explanation helps! Let me know if you have any further questions.

A potential difference of 2.0 V is applied across a wire of cross sectional area 2.5 mm^2. The current which passes through the wire is 3.2 × 10-3 A. What is the resistance of the wire?