divide 1000 among a,b,c in such a way that a gets 120 more than b and b gets rs 110 more than c .hw much each get
a+b+c = 1000
a = b+120
b = c+110
b+120 + b + c = 1000
c+110+120 + c+110 + c = 1000
3c+340 = 1000
3c = 660
...
To divide 1000 among a, b, and c, we need to find the values for a, b, and c that satisfy the given conditions. Let's break down the problem step by step:
1. We know that a gets 120 more than b. So, let's assume b = x.
a = b + 120
= x + 120
2. We also know that b gets Rs 110 more than c. So, let's assume c = y.
b = c + 110
= y + 110
3. The sum of a, b, and c should be equal to 1000.
a + b + c = 1000
Now, substitute the values of a and b from step 1 and 2 into the equation from step 3:
(x + 120) + (y + 110) + y = 1000
Simplifying the equation:
x + y + y + 120 + 110 = 1000
2y + x + 230 = 1000
2y + x = 770
At this point, we have to make an assumption for the value of one of the variables. Let's assume c = y = 100.
Substituting this value into the equation:
2(100) + x = 770
200 + x = 770
x = 770 - 200
x = 570
Now we know the value of b, which is x = 570.
Next, we can substitute this value back into the equation to find a:
a = x + 120
= 570 + 120
= 690
Finally, we have the values for a, b, and c:
a = 690
b = 570
c = 100
Thus, a gets Rs 690, b gets Rs 570, and c gets Rs 100.