a classroom is 11m long and 8m wide and 5m height .find the sum of area of its floor and the four wall.
Given,
length = 11 m
breadth = 8 m
height = 5 m
We know,
Area of floor = Area of rect.
= l*b
= 11*8
= 88 m
Area of 4 walls = 2(l+b)h
= 2(11+8)*5
= 2 * 19 * 5
= 190 m²
It is not ft it is meters
U gave wrong answer
To find the sum of the area of the floor and the four walls, we need to calculate the area of each component separately and then add them together.
First, let's calculate the area of the floor:
Area of the floor = length × width
= 11m × 8m
= 88 square meters
Next, let's calculate the area of the four walls:
Since the classroom has a height of 5 meters, we will consider the four walls as rectangles.
The area of each wall will be equal to its height multiplied by its corresponding length or width.
For the two longer walls:
Area of each longer wall = height × length
= 5m × 11m
= 55 square meters
For the two shorter walls:
Area of each shorter wall = height × width
= 5m × 8m
= 40 square meters
Now, let's calculate the sum of all these areas:
Sum = Area of floor + 2 × Area of longer walls + 2 × Area of shorter walls
= 88 + 2 × 55 + 2 × 40
= 88 + 110 + 80
= 278 square meters
Therefore, the sum of the area of the floor and the four walls of the classroom is 278 square meters.
A = L*W + 2W*h + 2L*h.
A = 11*8 + 2(8*5) + 2(11*5) = 278 ft^2.