A taxicab charges $2.50,plus$1.78 per kilometer. How long is a trip that costs 21.19?

2.5 + 1.78x = 21.19

1.78x = 18.69

x = 10.5 km

To determine the length of the trip, we need to find the number of kilometers traveled.

Let's assume the distance traveled is represented by 'x' kilometers.

The cost of the trip consists of a flat fee of $2.50 plus $1.78 for each kilometer. So, the cost can be represented by the equation:

Cost = $2.50 + $1.78 * x

We are given that the cost of the trip is $21.19, so we can set up the equation:

$21.19 = $2.50 + $1.78 * x

To solve for 'x,' we'll subtract $2.50 from both sides of the equation:

$21.19 - $2.50 = $1.78 * x

$18.69 = $1.78 * x

Now, we'll divide both sides of the equation by $1.78 to isolate 'x':

x = $18.69 / $1.78

Calculating this, we get:

x ≈ 10.49 kilometers

Therefore, the length of the trip is approximately 10.49 kilometers.

To determine the length of the trip that costs $21.19, we can start by subtracting the base fare from the total fare. The base fare is $2.50.

So, $21.19 - $2.50 = $18.69.

Now, we need to figure out how many kilometers were traveled to cost $18.69. We know that each kilometer costs $1.78.

To find the distance, we'll divide the remaining fare ($18.69) by the cost per kilometer ($1.78):

$18.69 ÷ $1.78 = 10.49.

Therefore, the trip was approximately 10.49 kilometers long.

8-3/4c=5