If 0.01% of electrons are removed from 18 gm water, then calculate the charge produced
in the water.
.01 mole= .01*Avagnumber*e
= .01*6.02E23*1.6E-19 coulomb
= about.1E4 coulomb in my head
To calculate the charge produced in the water, we need to know the number of electrons in 18 grams of water. We can then calculate the charge by multiplying the number of electrons by the fundamental charge (e).
Here are the steps to get the answer:
Step 1: Find the number of particles in 18 grams of water.
- Calculate the molar mass of water (H2O):
- The molar mass of hydrogen (H) is approximately 1 gram/mole.
- The molar mass of oxygen (O) is approximately 16 grams/mole.
- The molar mass of water (H2O) = 2 * (1 gram/mole) + 16 grams/mole = 18 grams/mole.
- Using the molar mass of water, calculate the number of moles in 18 grams of water:
- Number of moles = Mass / Molar mass = 18 grams / 18 grams/mole = 1 mole.
Step 2: Find the number of electrons in 1 mole of water.
- In 1 mole of water, there are 6.022 x 10^23 molecules of water (Avogadro's number).
- Each molecule of water contains 10 electrons (2 from each hydrogen atom and 6 from the oxygen atom).
- Therefore, the number of electrons in 1 mole of water = 6.022 x 10^23 molecules/mole * 10 electrons/molecule = 6.022 x 10^24 electrons.
Step 3: Calculate the charge produced by removing 0.01% of electrons from 1 mole of water.
- To calculate the charge, we need to multiply the number of electrons by the fundamental charge (e).
- The fundamental charge (e) is approximately 1.6 x 10^-19 coulombs.
- Calculate the charge produced:
- Charge = 0.01% * (6.022 x 10^24 electrons) * (1.6 x 10^-19 coulombs/electron) = 0.0001 * (6.022 x 10^24) * (1.6 x 10^-19) coulombs.
Step 4: Simplify the expression to get the final answer.
- Multiply the coefficients: 0.0001 * 6.022 * 1.6 = 9.6352 x 10^-22 coulombs.
Therefore, the charge produced in the water is approximately 9.6352 x 10^-22 coulombs.