When a number is a multiple of 6,what are the possible values for the ones digit?

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To determine the possible values for the ones digit when a number is a multiple of 6, we need to understand the divisibility rule for 6.

The rule states that a number is divisible by 6 if it is divisible by both 2 and 3.

1. For a number to be divisible by 2, it must have an even ones digit. The possible values for the ones digit are 0, 2, 4, 6, and 8.

2. For a number to be divisible by 3, the sum of its digits must be divisible by 3. Since we are only considering the ones digit, the possible values that make the sum divisible by 3 are 3, 6, and 9.

Therefore, the possible values for the ones digit when a number is a multiple of 6 are 0, 2, 4, 6, 8, and 9.

To determine the possible values for the ones digit when a number is a multiple of 6, we need to understand the divisibility rule of 6. A number is divisible by 6 if it is divisible by both 2 and 3.

A number ending in an even digit, such as 0, 2, 4, 6, or 8, is divisible by 2.

To determine if a number is divisible by 3, we need to check if the sum of its digits is divisible by 3. For example, if 235 is divisible by 3, we add up the digits: 2 + 3 + 5 = 10. Since 10 is not divisible by 3, 235 is not divisible by 3. However, if we take the number 246, the sum of its digits is 2 + 4 + 6 = 12, which is divisible by 3. Hence, 246 is divisible by 3.

Therefore, to find the possible values for the ones digit when a number is a multiple of 6, we need to find the numbers that are divisible by both 2 and 3. The numbers that satisfy this condition are:

0, 2, 4, 6, and 8.

So, the possible values for the ones digit of a number that is a multiple of 6 are 0, 2, 4, 6, and 8.

Well, consider the multiples:

[6, 12, 18, 24, 30, 36, 42, 48, 54, 60, ...]

Eventually, you run into repeating digits in the one's place.

You should be able to figure it out from there.