Henry is building a fence in his backyard for his new puppy. he has 36 feet of fencing and wants a fence in a rectangular area. what is one set of whole number dimension of the fenced in area?
What are the multiples of thirty-six?
each could be 9ft with plenty of other answers
To find the dimensions of the fenced-in area, we need to make use of the given information. Here's how you can calculate it:
1. Let's assume the length of the rectangular area is "L" and the width is "W" in feet.
2. The formula to calculate the perimeter of a rectangle is P = 2L + 2W, where "P" represents the perimeter.
3. In this scenario, the perimeter is given as 36 feet. So we can write the equation as: 36 = 2L + 2W.
To find one set of whole number dimensions, we can use trial and error by putting different values for L and solving for W:
1. Let's start by assuming L = 10 feet.
- Substitute L = 10 in the equation: 36 = 2(10) + 2W.
- Simplify: 36 = 20 + 2W.
- Solve for W: 2W = 36 - 20 = 16, then divide both sides by 2: W = 8.
- So, when L = 10, W = 8, the dimensions are 10 feet by 8 feet.
2. Let's try another set of values, assuming L = 12 feet.
- Substitute L = 12 in the equation: 36 = 2(12) + 2W.
- Simplify: 36 = 24 + 2W.
- Solve for W: 2W = 36 - 24 = 12, then divide both sides by 2: W = 6.
- So, when L = 12, W = 6, the dimensions are 12 feet by 6 feet.
Therefore, two possible sets of whole number dimensions for the fenced-in area are 10 feet by 8 feet and 12 feet by 6 feet.