Determine the number of moles of oxygen in 1 mol of dinitrogen tetraoxide
N2O4= N 2×14.01g/mol= 28.02g/mol
O 4×16.00g/mol= 64.00g/mol
N2O4= 92.02g/mol
I can't get the right formula to solve the rest. Please help and thank you
I think I was trying to find the molar mass oops.
But aren't there 4 mol of oxygen in dinitrogen tetraoxide?
To determine the number of moles of oxygen in 1 mole of dinitrogen tetraoxide (N2O4), you need to use the given molar mass values for nitrogen (N) and oxygen (O), as well as the molar mass of N2O4.
You correctly calculated the molar mass of N2O4 to be 92.02 g/mol.
Now, let's break down the formula N2O4:
- N2 refers to two nitrogen atoms, each with a molar mass of 14.01 g/mol
- O4 refers to four oxygen atoms, each with a molar mass of 16.00 g/mol
Next, you need to determine the molar mass of the oxygen atoms in N2O4:
Molar mass of O = 4 × (molar mass of a single O atom)
= 4 × 16.00 g/mol
= 64.00 g/mol
Therefore, for each mole of N2O4, there are 64.00 g of oxygen atoms.
To find the number of moles of oxygen in 1 mole of N2O4, you can use the molar mass ratio:
Moles of oxygen = mass of oxygen / molar mass of oxygen
= 64.00 g / 16.00 g/mol
= 4.00 mol
So, there are 4 moles of oxygen in 1 mole of dinitrogen tetraoxide (N2O4).
Remember to always check your units throughout the calculations to ensure they are consistent.
in one mole of N2O4, there are
moles of N2: one
moles of O2: two
Your work makes no sense, and is off on a tangent.