Question
In an experiment a gas was found to obey the following equation of state:
(P + 10^3)V = 2.5 x 10^4 J
Find the work done when the gas expands from 1 m3 to 3 m3.
_______
the answer is suppose to be
2.55 x 104J
____________ what i did so far
2 ways i approached this question...first way was the use V as 2 (that is Vf- Vi) and solve for P
Then i plug in equation
W = p delta V
got 2.7 X 10^4
____________ nxt way
i found the values of p using V as 1 and 3
Then, i found the work for each of the pressure i calculated, then added...got like 3.8 x 10^4
i'm baffled