The apparent weight of cube in liquid with relatibe density 0.9
To determine the apparent weight of a cube in a liquid with a relative density of 0.9, you need to follow these steps:
1. Understand the concept of relative density: Relative density compares the density of a substance to the density of another substance, usually water. It is calculated by dividing the density of the substance by the density of the reference substance.
2. Calculate the density of the liquid: If you know the relative density and the density of the reference substance (usually water), you can calculate the density of the liquid by multiplying the relative density by the density of the reference substance. In this case, if the relative density of the liquid is 0.9, and the density of water is approximately 1000 kg/m³, you can calculate the density of the liquid as 0.9 * 1000 kg/m³ = 900 kg/m³.
3. Calculate the apparent weight of the cube in the liquid: The apparent weight of an object in a fluid is the difference between its actual weight in air and its buoyant force in the fluid. The buoyant force is given by the Archimedes' principle, which states that the buoyant force on an object submerged in a fluid is equal to the weight of the displaced fluid.
To calculate the apparent weight, you need to know the weight of the cube in air and the weight of the displaced fluid.
- Calculate the weight of the cube in air: This can be determined by multiplying the mass of the cube by the acceleration due to gravity. The equation is weight = mass * g, where g is approximately 9.8 m/s².
- Calculate the weight of the displaced fluid: This can be calculated by multiplying the density of the liquid by the volume of the cube submerged in the liquid. The equation is weight = density * volume * g.
- Subtract the weight of the displaced fluid from the weight of the cube in air to get the apparent weight.
By following these steps, you can determine the apparent weight of a cube in a liquid with a relative density of 0.9.