Angela is twice as old as clara. Seven years ago, the sum of their ages was 16. How old is clara now?
7+16 *2= a
16*2= 32 + 7 = 39
a = 39
a = 2 c
a-7 + c-7 = 16
2 c + c - 14 = 16
3c = 30
c = 10
Hmm be sure to put the numbers back in to check.
a = 20 and c = 10
13 + 3 = 16
To solve this problem, we can set up a system of equations. Let's call Angela's current age "A" and Clara's current age "C".
From the problem, we know that Angela is twice as old as Clara. So, we can write the equation:
A = 2C ...(1)
We also know that seven years ago, the sum of their ages was 16. This means that seven years ago, Angela's age was A - 7, and Clara's age was C - 7. So we can write the equation:
(A - 7) + (C - 7) = 16 ...(2)
Now we have a system of two equations (equations 1 and 2) that we can solve to find the values of A and C.
First, let's substitute the value of A from equation 1 into equation 2:
(2C - 7) + (C - 7) = 16
Simplifying the equation:
3C - 14 = 16
Add 14 to both sides:
3C = 30
Divide both sides by 3:
C = 10
So, Clara is currently 10 years old.